In dealing with some of the data, we want to be able to use the "rounding" method, but C # uses the "four six into 50% pairs" method, such as the following example, is the "four six into 50% pairs" results obtained:Double D1 = Math.Round (1.25, 1);//
Hi all,After I investigated CCR below, I found an rounding issue. The issue is, we can get different resultBetween Linux and Windows platform when we do the decimal rounding with string format or printfunction.Refer to the screenshots first.Pic1
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
double
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
Code
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
double d1 =
When processing some data, we hope to use the "Rounding" method, but C # uses the "four homes, six homes, five into two" method, as shown in the following example, the result is obtained using "four homes, six homes, and five into two:
Double d1 =
Reprint Source: HTTP://BLOG.CSDN.NET/YF210YF
Matlab takes the whole function: fix, floor, ceil, round. The rounding function is useful in programming. First, take the whole function 1. To 0 rounding (truncated rounding)
fix-to 0 rounding (Round
Problem
Recently I tried to use rounded values in my application, and my users were divided about the computational problems in the report application. All of the code is in T-SQL, but I think the report problem is closely related to the data type
JS only retains integers, rounded up, rounding, and rounding down functions1. Discard the fractional part, preserving the whole number of partsparseint (5/2)2. Rounding up, with decimals on the integer part plus 1Math.ceil (5/2)3, rounded.Math.Round
1. Discard the fractional part, preserving the integer part parseint (5/2) 2. Rounding up, with decimals on the integer part plus 1math.ceil (5/2) 3, rounded. Math.Round (5/2)1. Discard the fractional part, preserving the whole number of
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